0=-16t^2+765t+65

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Solution for 0=-16t^2+765t+65 equation:



0=-16t^2+765t+65
We move all terms to the left:
0-(-16t^2+765t+65)=0
We add all the numbers together, and all the variables
-(-16t^2+765t+65)=0
We get rid of parentheses
16t^2-765t-65=0
a = 16; b = -765; c = -65;
Δ = b2-4ac
Δ = -7652-4·16·(-65)
Δ = 589385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-765)-\sqrt{589385}}{2*16}=\frac{765-\sqrt{589385}}{32} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-765)+\sqrt{589385}}{2*16}=\frac{765+\sqrt{589385}}{32} $

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